128x^2-8x-3=0

Solution for 128x^2-8x-3=0 equation:

Simplifying
128x2 + -8x + -3 = 0

Reorder the terms:
-3 + -8x + 128x2 = 0

Solving
-3 + -8x + 128x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(-1 + -8x)(3 + -16x) = 0

Subproblem 1
Set the factor '(-1 + -8x)' equal to zero and attempt to solve:

Simplifying
-1 + -8x = 0

Solving
-1 + -8x = 0

Move all terms containing x to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + -8x = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -8x = 0 + 1
-8x = 0 + 1

Combine like terms: 0 + 1 = 1
-8x = 1

Divide each side by '-8'.
x = -0.125

Simplifying
x = -0.125
Subproblem 2
Set the factor '(3 + -16x)' equal to zero and attempt to solve:

Simplifying
3 + -16x = 0

Solving
3 + -16x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -16x = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -16x = 0 + -3
-16x = 0 + -3

Combine like terms: 0 + -3 = -3
-16x = -3

Divide each side by '-16'.
x = 0.1875

Simplifying
x = 0.1875
Solution
x = {-0.125, 0.1875}